Re: Barycentric to cartesian?

From: "Ron Francis" <ronfrancis@xxxxxxxxxxx>
Date: Tue, 22 Jul 2008 22:32:45 +0930

"Kaba" <none@xxxxxxxx> wrote in message
news:MPG.22efca82f5cffacf9896d8@xxxxxxxxxxxxxxxxx

For example, it could be stated that a point P on the triangle ABC
satisfies:

P = uA + vB + wC

Given this relation, the conversion to cartesian is directly given.

Oh, is it that easy?
I couldn't see the forest for the trees.
Thanks Kaba, much appreciated.

Regards,
Ron Francis
www.RonaldFrancis.com

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