Re: integration of a continuous function
- From: jim <".sjedgingN0sp"@m@xxxxxxx>
- Date: Wed, 25 Feb 2009 09:12:18 -0600
illywhacker wrote:
is sufficiently oversampled.
Jim, I do not know why you feel obliged to try to explain to me
I didn't feel obliged not even a little bit. You asked me a question. Now your
whining because I chose to provide a response.
Why would he want to integrate to do this? As far as I know, he did
not talk about a moving
average filter. He is integrating, that is, inverse differentiating.
No you are right. I have very little information on what he has tried or why he
thinks what he has tried didn't work. But you want him to invent a continuous
function so that he can do some math on that. Which frankly, in view of what
little info he has revealed, IMO is just plain silly.
-jim
.
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