Re: consistency
- From: Andor <andor.bariska@xxxxxxxxx>
- Date: Thu, 13 Nov 2008 12:49:14 -0800 (PST)
On 13 Nov., 02:00, Randy Yates <ya...@xxxxxxxx> wrote:
Andor <andor.bari...@xxxxxxxxx> writes:
Randy Yates wrote:
Rune Allnor <all...@xxxxxxxxxxxx> writes:
On 10 Nov, 14:32, Randy Yates <ya...@xxxxxxxx> wrote:
HardySpicer <gyansor...@xxxxxxxxx> writes:
What is consistency as regards random variables. I know that to be
unbiased we have E[x] = the actual mean but does consistency mean that
an estimator could be unbiased yet not consistent? What in words does
this mean?
Hi Hardy,
[mcdonough] defines an estimator x_n(_y_), where _y_ is a
length-n vector, as "consistent" when it has the property
that, for an small number e,
lim_{n --> infty} P( | x_n(_y_) - x | > e) = 0.
This is also called "convergence in probability" (see, e.g.,
[viniotis]).
Maybe this is the same as you said, but my understanding
is that a consistent estimator is an estimator which
has the two properties that
1) the estimate is unbiased
I think that's true.
But it's not true (see below).
2) the variance vanishes as the number of samples goes to
infinity.
I think so, Rune.
This second point is necessary for consistency.
If you assume that the estimator x_n results from estimating some
parameter from n i.i.d. observations and let n->oo, then a consistent
estimator may be biased for all n but the bias has to disappear as n-
oo ("asymptotically unbiased") and the variance has to disappear,too.
Hi Andor,
At this point, all I can do is say "OK, if you say so." I'm
not sure how to show this to myself rigorously (analytically),
so I guess I'll just shutup...
It would be very interesting to me, however, if you could explain why
you had to condition that statement with the assumption that the
estimator inputs are iid. Aren't there potentially consistent-but-biased
estimators for other classes of random processes?
Hi Randy
It's more a matter of convenince. You need a sequence of random
variables x_n in the first place (consistency is a convergence result,
so you need a sequence that converges to somewhere). Estimators on
growing sets of "data" (itself random varibles) are typical sequences
that can converge. Assuming the "data" to be i.i.d just makes things
simple.
Regards,
Andor
.
- References:
- consistency
- From: HardySpicer
- Re: consistency
- From: Randy Yates
- Re: consistency
- From: Rune Allnor
- Re: consistency
- From: Randy Yates
- Re: consistency
- From: Andor
- Re: consistency
- From: Randy Yates
- consistency
- Prev by Date: Re: Equalization using DFT
- Next by Date: New DSP audio website
- Previous by thread: Re: consistency
- Next by thread: Re: consistency
- Index(es):
Relevant Pages
|