Re: Two DSP theoretical questions



On Thu, 14 Feb 2008 12:28:06 -0600, scc28 wrote:
(top posting fixed)

On Tue, 12 Feb 2008 17:06:13 -0600, scc28 wrote:

Hi, I have two questions which seem somewhat basic but confuse me:

1. We know that a sequence has to be "summable" to have Fourier
Transform (ie. DTFT converges). Is this the same as saying that a
"bounded" sequence will have Fourier Transform?

No. If x_n = 1 for all n from 0 to infinity, then the sum of all x_n is

infinite, even though x_n is pretty strongly bounded.

2. Do all sequences have z-transform? In other words, can a sequence
have z-transform with no ROC (region of convergence)?

Randy's answer: nuh uh. The z transform is the result of a sum, if the
sum doesn't converge for any z then it's 'answer' is meaningless.

Hi thanks for the helpful insight. I guess I need to rephrase my 2nd
question. If a z transform of a sequence does not have any ROC, can it
still be written in a closed mathematical expression?

thanks in advance

Yes:

X(z) = e^(j * theta(z)) * infinity

That's assuming you're good enough to solve an unbounded summation for
the phase angle, of course.

--
Tim Wescott
Control systems and communications consulting
http://www.wescottdesign.com

Need to learn how to apply control theory in your embedded system?
"Applied Control Theory for Embedded Systems" by Tim Wescott
Elsevier/Newnes, http://www.wescottdesign.com/actfes/actfes.html
.



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