Re: CTFT of a discrete signal
- From: glen herrmannsfeldt <gah@xxxxxxxxxxxxxxxx>
- Date: Tue, 14 Aug 2007 11:12:46 -0800
NewLine wrote:
What I would like to do (as a first step in some reasoning) is to take the (continuous time) Fourier transform (CTFT) of a discrete 'signal/function'.
I think (I am trying to proof that to myself) that this should be equal to the DTFT of that signal, but I am not sure if that is 100% correct.
When working in the discrete domain and using the DTFT my signal is just a bunch of numbers I think. (or not?)
However it 'feels' to me that to be able to take the CTFT of that discrete signal I should represent the numbers by scaled diracs.
Among the transform pairs there is
discrete <--> periodic
Applying that twice, you get
discrete periodic <--> discrete periodic
which is the DTFT.
The transform will be discrete (or scaled delta functions)
if the original is periodic, discrete or not.
-- glen
.
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