Re: FIR Hilber Transformer

Jerry Avins wrote:
throws the communication out of order.
Top post is confusing because it

I. R. Khan wrote:

But odd symmetric coefficients do not necessarily make a HT. A
differentiator also has odd symmetric coefficients.

Clay wrote:

By simple inspection you can see if the phase repsonse matches that of
a Hilbert transformer. The coefs need to have odd symmetry. This is
necessary in order to have a 90 degree phase shift.

I assume you want the HT to occupy the widest bandwidth between DC and
Fs/2. Number the coefficients c[n] according to their position from the
center, negative for one side, positive. For an odd number of
coefficients, c[0] is zero, and so are all other even-numbered ones. The
odd numberer coefficients, multiplied by their indices, will be a
constant.

Are you talking about windows based design? This does not seem true for other designs. For example, for the following HT
{-1/16, 0, -9/16, 0, 9/16, 0, 1/16}
I found a very nice chapter on HTs in Rick's book, and got the information that I needed. Thanks for your reply.

I leave the cases of an even number of taps and the proper
constant for unity gain as an exercise.

Jerry
.

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