Re: How does sampling frequency affects a digital filter ?
- From: "Rune Allnor" <allnor@xxxxxxxxxxxx>
- Date: 13 Mar 2006 05:03:51 -0800
mel wrote:
Hello,
I am writing a digital filter but it seems that according to
the sampling frequency my filter should change ... how does this
happens ? being a digital filter there is no such a thing as sampling
frequency, right ?
Interesting question! I am not sure it is what you mean, but I
interpret it as "If the signal is specified in discrete-time domain,
the signal is never sampled and there is no such thing as a sampling
frequency." I agree, this is a valid question.
One more thing ... it seems that the cut off frequency should
affect my filter too ... the cut off frequency is the bandwidth of the
transmitting channel, right ? How should it affect the filter ?
The key here is that the filter in frequency domain is specified in
terms of "normalized frequencies." If we agree to use "time" as
name for the running variable in signal domain, and "fequency"
in Fourier domain (we could have used space and wavenumber,
or something else), the discrete-time signal has a limited-width
spectrum. To make sense of it all, and relate it to the more intuitive
case of a sampled signal, we speak of a "normalized sampling
frequency" with sampling period 1. If we do that, all the T factors
in the forward and inverse Fourier transforms disappear, and we
still can speak a comprehensible language.
In that case, the filter cut-off frequency is still well-defined,
relative
to the normalized sampling frequency.
f_c = F_c/F_s = f_c*T/(f_s*T) = f_c*1/1*1 = f_c.
In fact, most filter design packages work in this normalized domain,
introfducing the T factor only when needed.
Sorry if these questions sounds dumb,
No, they certainly are not. These are the kinds of questions that
either make you shy DSP as a dicipline, or make you gain insight.
Rune
.
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