Re: Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- From: "Michael" <femi@xxxxxxxxxxxxxxxxxx>
- Date: Sat, 14 Jan 2006 11:48:53 +0100
Hi,
> you can also be having overflow problems internal to the filter
> calculations...
>
> does the distortion improve if you reduce the input signal amplitude?
>
> what type of distortion are you having?
>
> Mar
>
I have tested the Chebyshev with different amplitudes of the input signal. I
know that problem in connection with my FIR filters. There I got a strange
output by filtering a sinus wave, which showed a "huge"(?) amplitude.
All in all, it is the problem of coming closer to the Nyquist freq, e.g. I
have 44100Hz input, cutoff 0.5 or 0.495, and strange things happen:
type of distortion: Well, it is different to describe, so you can find my
output files here:
http://www-user.tu-chemnitz.de/~femi/cheb/
0.5c means cutoff value
4p stands for number of poles
Ciao, Michael
.
- References:
- Chebyshev IIR - how to achieve band-pass tranform?
- From: Michael
- Re: Chebyshev IIR - how to achieve band-pass tranform?
- From: Rune Allnor
- Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- From: Michael
- Re: Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- From: Rune Allnor
- Re: Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- From: Mark
- Chebyshev IIR - how to achieve band-pass tranform?
- Prev by Date: Audio
- Next by Date: Re: Ways of implementing a Hilbert Transform
- Previous by thread: Re: Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- Next by thread: Re: Chebyshev IIR - cutoff frequency 0.5 leads to distortion?
- Index(es):
Relevant Pages
|