Re: Fourier Transform Question for Pulsed CW and 802.11b DSSS
- From: "Clay S. Turner" <Physics@xxxxxxxxxxxxx>
- Date: Mon, 31 Oct 2005 11:33:38 -0500
<radio913@xxxxxxx> wrote in message
news:1130773278.863889.128080@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
>>
>> = 2a * sinc(wa)
>>
>
>
> I would like to see where the
> pulse repetition interval comes into
> play here (PRI), and how the spacing
> of the frequencies are 1/PRI, and how
> the spacing of the sinx/x lobes are
> 1/T, where T is the "on" period of the
> CW pulse.
>
Hello Slick,
Since we now know that a pulse with width 2a has a FT of 2a since(wa), then
to see the pulse repetition interval, find the zeros of the sinc function.
Since the sinc is a fraction with nonzero denominator, it suffices to find
the zeroes of the numerator recalling the 0/0 case at the origin needs
special handling. The zeroes of sin(x) occur at multiples of pi.
So the zeroes of sinc(wa) occur where wa = n*pi and n is an integer except
when n=0. So solve for w and you find w(n) = n*pi/a. Since n is an integer
with the aforementioned caveat, the repetition interval is simply pi/a.
IHTH,
Clay
.
- References:
- Fourier Transform Question for Pulsed CW and 802.11b DSSS
- From: radio913
- Re: Fourier Transform Question for Pulsed CW and 802.11b DSSS
- From: Clay S. Turner
- Re: Fourier Transform Question for Pulsed CW and 802.11b DSSS
- From: radio913
- Fourier Transform Question for Pulsed CW and 802.11b DSSS
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