Re: Fourier Transform Question for Pulsed CW and 802.11b DSSS
- From: "Clay S. Turner" <Physics@xxxxxxxxxxxxx>
- Date: Mon, 31 Oct 2005 07:05:34 -0500
<radio913@xxxxxxx> wrote in message
news:1130736886.809206.125170@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> Clay S. Turner wrote:
>>
>> 1st show the FT of a pulse is a sinc function. This integration is
>> straight
>> forward in the integral only needs to be done over the support of the
>> pulse.
>>
>
> Could you show us this "straight forward"
> integration?
>
define pulse
Rect(x) = 1 when |x| <a
= 0 otherwise
FT(w) = integral - infty to infty of Rect(x) exp(-jwx) dx
= integral -a to a of exp(-jwx) dx
= exp(-jwx)/(-jw) evaluated at a minus exp(-jwx)/(-jw)
evaluated at -a
recall Euler's theorem exp(jx) = cos(x)+j sin(x)
cos(wa)-j sin(wa) cos(-wa) - j sin(-wa)
= --------------------- - ----------------------
-jw -jw
Now recall symmetry properties cos(-x) = cos(x) and sin(-x) = -
sin(x)
= (cos(wa) - cos(wa) - j sin(wa) - j sin(wa)) / (-jw)
= 2 sin(wa)/w
= 2a * sin(wa)/(wa)
= 2a * sinc(wa)
IHTH,
Clay
.
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