Re: Basic SQL
- From: Stefan Rybacki <stefan.rybacki@xxxxxxx>
- Date: Thu, 14 Jul 2005 11:41:34 +0200
John Gilson wrote:
Ok you're right, didn't recognize that the op wanted to get distinct values. But one subselect is still enough"Stefan Rybacki" <stefan.rybacki@xxxxxxx> wrote in message news:3jlhr8Fqd4cmU2@xxxxxxxxxxxxxxxxx
John Gilson wrote:
"MS" <mesemailoffers@xxxxxxxxxxx> wrote in message news:1121280375.735695.277470@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
I am trying to write a sql statement that gives me the records that have multiple values for column b, but cannot figure it out - can someone help?
My table is as follows:
ID Value 1234 S 1234 S 1234 X 4444 S 5555 X 5555 Y
I want to see what records have two distinct values for the "Value" column. The results of the query when running against the above data should be as follows:
ID Value 1234 S 1234 X 5555 Y 5555 X
Any help would be appreciated.
Thanks!
SELECT ID, Value FROM (SELECT DISTINCT id, value FROM T) AS T WHERE EXISTS (SELECT * FROM T AS T1 WHERE T1.ID = T.ID AND T1.Value <> T.Value)
-- JAG
Ui two subselects? :/ I even don't like the one I used in my solution ;)
Regards Stefan
Given the original poster's stated input and required output, your query doesn't do the trick.
-- JAG
SELECT DISTINCT ID,VALUE FROM table2 T2 WHERE EXISTS (SELECT * FROM table2 WHERE ID=t2.ID AND VALUE<>T2.VALUE)
Regards Stefan .
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