Re: is there a better way to do this?
- From: Ben <benalvey@xxxxxxxxx>
- Date: Wed, 20 Feb 2008 10:10:15 -0800 (PST)
On Feb 20, 8:30 am, "fitzjarr...@xxxxxxx" <fitzjarr...@xxxxxxx> wrote:
On Feb 20, 6:44 am, Ben <benal...@xxxxxxxxx> wrote:
On Feb 19, 5:04 pm, "fitzjarr...@xxxxxxx" <fitzjarr...@xxxxxxx> wrote:
On Feb 19, 2:32 pm, Ben <benal...@xxxxxxxxx> wrote:
10.2.0.2 EE
Is there a more logical sql statement to get the same results than
what I am running here?
create table t (a number, b number);
insert into t values (1, 1);
insert into t values (1, 2);
insert into t values (2, 3);
insert into t values (3, 2);
insert into t values (4, 4);
insert into t values (4, 5);
insert into t values (5, 1);
insert into t values (6, 8);
commit;
select a.a, a.b
from t a, (
select b, count(distinct a)
from t
group by b
having count(distinct a) > 1) b
where a.b = b.b
A B C D
---------- ---------- -------------------- --------------------
5 1 a a
1 1 a a
3 2 a a
1 2 a a
What I am wanting are the values for A where B is the same.
What, exactly, does that last sentence mean?
David Fitzjarrell- Hide quoted text -
- Show quoted text -
in the original post my table definition doesn't have a column C or D
but the output shows them. I removed those columns from my post to try
to avoid confusion and forgot to remove them from the output of the
query.- Hide quoted text -
- Show quoted text -
You need to read the text which was referenced, and it wasn't your
tacked-on follow-up. Apparently David Portas could decipher this and
provide a reasonable alternative.
David Fitzjarrell- Hide quoted text -
- Show quoted text -
"What I am wanting are the values for A where B is the same."
yes, I can see where it is confusing.
Looking at the dataset that I created in the insert statements, you'll
see all the values for column B. I want a listing of those records
with duplicate B values. For this dataset the values of B that have
duplicates are 1 and 2. I would want all records that have either a 1
or 2 for B. I needed a sql statement to return that information
without already knowing that 1 and 2 were the values that had
duplicates.
.
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