Re: hierarchical query - returning a treewalked subset
- From: daoudamjad@xxxxxxxxxxxxxx
- Date: Thu, 15 Nov 2007 11:25:14 -0800 (PST)
On Nov 9, 10:52 pm, DA Morgan <damor...@xxxxxxxxx> wrote:
SpaceMarine wrote:
On Nov 9, 4:00 am, havardk <hrkristiansen...@xxxxxxxxxxx> wrote:
Ah... Now I understand your problem. Avoiding duplicates complicates
matters, because then you will have to traverse the tree the other way
to see if any other candidate is listed higher, starting from all rows
that satisfy your "start with" criteria.
The select below is even slower, but still works for this problem. I
suspect there is an easier way to solve this :-)
yeah. i think it may be better just to keep the resultset w/ dupes,
and then run it thru a scrubber in application code (which is what im
doing now). my C# method loops thru the resultset (which is usually
pretty small), and if a row is LEVEL 1, it loops thru the resultset
again looking for a > LEVEL 1 row. if found, it knows the original-row
is a child and shouldnt be a root, so it flags it for removal. after
the initial pass all removals are performed (in a reverse loop to
preserve row-number integrity), each one cascading down to remove the
removal-row's children. works.
thanks for the suggestions!
sm
Take any query that produces a result set in Oracle.
Wrap it with parentheses so it becomes an in-line view.
SELECT DISTINCT from it.
--
Daniel A.Morgan
Oracle Ace Director & Instructor
University of Washington
damor...@xxxxxxxxxxxxxxxx (replace x with u to respond)
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