Re: split string into an array by some delimiter using 9i?

On Sep 28, 10:56 am, jobs <j...@xxxxxxxxxx> wrote:
apparently I can't do this in 9i?

myarray := split(sendto, ',');

Any easy way to do it?

Thanks fo rnay help or information.

Here's a function that will do what you want.

FUNCTION split_text(text_ids IN VARCHAR2
,delim VARCHAR2
,return_nulls BOOLEAN) RETURN varchar_tab
PIPELINED IS
vn_idx PLS_INTEGER;
vc_text_ids VARCHAR2(32767) := text_ids;
vc_next_string VARCHAR2(32767);
BEGIN
LOOP
vn_idx := instr(vc_text_ids, delim);
IF vn_idx > 0
THEN
vc_next_string := substr(vc_text_ids, 1, vn_idx - 1);
IF vc_next_string IS NOT NULL
OR return_nulls
THEN
PIPE ROW(vc_next_string);
END IF;
vc_text_ids := ltrim(substr(vc_text_ids, vn_idx +
length(delim)));
ELSE
IF vc_text_ids IS NOT NULL
OR return_nulls
THEN
PIPE ROW(vc_text_ids);
END IF;
EXIT;
END IF;
END LOOP;
RETURN;
END split_text;

.