Re: Why channel decorrelation can improve compression?

On Jun 18, 12:04 pm, danilobrambi...@xxxxxxxxxx wrote:
(r + 2g + b) / 4 -> y

b - y -> cb

r - y -> cr

Hi,

consider that you will have to use an extra bit to the y channel to
make the transform completely reversible, otherwise you could lose a
bit in the g channel. For example (r=0, g=0, b=0) and (r=0, g=1, b=0)
both map to (0,0,0): in one of the two cases when reversing the
transform a value will be worng.

So long,
Stefano
.

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