Re: computation of square root & reciprocal calculation

And about the reciprocal square root of X according
to CORDIC (or more precisely speaking to digit-by-digit method).

One should multiply X to the (1+2**-i)(1+2**-i) or to the
(1-2**-i)(1-2**-i)
depends on correspondingly less or more than 1 the current value of X.
i = 1,2,...n (n= word length) and 0,5 <X <1,5
Simultaneously one should multiply Y correspondingly to the (1+2**-i)
or to the (1-2**-i).

And after n iterations : the result X is 1 with the n-bit accuracy.
and the result Y is the reciprocal square root of X.

.