Re: Control Theory Experiments

On 20 Apr 2006 07:09:55 -0700, ann.tighe@xxxxxxxxx wrote:

The original author's experiments use a transfer function

X(s)= (0.00375/((s+0.15)*(s+0.25)))*U

where U is the controller input to the system and X is the system
output.

From my reading I believe that to graph this in a time domain I have to
multiply it by 1/s and then get the inverse Laplace transform, am I on
the right track?

Can't really say anything to the topic. Just regarding the Laplace
transformation, the original of

F(s) = 0.00375 / ((s+0.15)*(s+0.25))

should be

f(t) = exp(-0.25t) - exp(-0.15t)

In general:

L(exp(-t/a)-exp(-t/b) / (a-b)) = 1/(1+as)(1+bs)

--
Regards,
Dmitry A. Kazakov
http://www.dmitry-kazakov.de
.