# Will the Ice Caps Melt?

*From*: jose <josefsoplar@xxxxxxxxx>*Date*: Tue, 22 Jan 2008 08:27:08 -0800 (PST)

Will the Ice Caps Melt?

By Jerome J. Schmitt

"The engineer has learned vastly more from the steam-engine than the

steam-engine will ever learn from the engineer."

-- Prof John B. Fenn, Nobel Prize, Chemistry, 2002

There is considerable debate over whether the "greenhouse gas" effect

will raise the temperature of the atmosphere by between 1-5°C over the

next 100 years. But even if you grant for the sake of argument the

Warmist claim that the earth's atmosphere will go up a full five

degrees Centigrade in temperature, Al Gore's claim that ocean levels

will rise 20 feet thanks to global warming seems to ignore the laws of

thermodynamics. I am no climatologist, but I do know about physics.

Anyone who has ever spent time in a temperate climate following a

snowy winter realizes that when the air temperature rises above 32°F

the snow and ice do not melt immediately. We may experience many balmy

early spring days with temperatures well above freezing while snow

drifts slowly melt over days or weeks. Similarly, lakes and ponds take

some time to freeze even days or weeks after the air temperature has

plunged below zero. This is due to the latent heat of freezing/

melting of water, a physical concept long quantified in

thermodynamics.

That aspect of basic physics seems to have been overlooked by

climatologists in their alarming claims of dramatic and rapid sea-

level rise due to melting of the Antarctic ice caps and Greenland

glaciers. But of course, we have learned that models predicting global

warming also failed to take account of precipitation, so overlooking

important factors ("inconvenient truths") should not cause much

surprise anymore.

The scientific data necessary to calculate the amount of heat

necessary to melt enough ice to raise ocean levels 20 feet is readily

available on the internet, and the calculations needed to see if polar

cap melting passes the laugh test are surprisingly simple. Nothing

beyond multiplication and division, and because we will use metric

measures for simplicity's sake, much of the multiplying is by ten or a

factor of ten.

Let's review the math. The logic and calculations are within the

grasp of anyone who cares to focus on the subject for minute or two,

and speak for themselves.

I should first mention that the only source of energy to heat the

atmosphere is the sun. The average energy per unit time (power) in

the form of sunlight impinging on the earth is roughly constant year-

to-year, and there are no means to increase or reduce the energy flux

to the earth. The question merely is how much of this energy is

trapped in the atmosphere and available to melt ice thus effecting

"climate change".

How much heat must be trapped to raise the atmospheric temperature by

a degree centigrade (or more) can be readily calculated, knowing the

mass of the atmosphere and the specific heat of air. Specific heat is

simply an empirically-determined quantity that corresponds to the

number of units of heat energy required to raise a specific mass of a

substance, in this case air, by 1 degree in temperature. A common

unit of energy familiar to most of us is the calorie. But for

simplicity, in this calculation I will use the MKS[*] metric unit of

the Joule (J), which, while perhaps unfamiliar to many readers in

itself, is the numerator in the definition of our common unit of

power, the Watt[†] = Joule/second.

The mass of the atmosphere can be found here. We also know that it is

principally composed of air, so without loss of accuracy in what is

essentially an "order of magnitude" calculation, it is fair to employ

the specific heat of air at constant pressure, Cp which also can be

referenced on the internet here. While this has a value that changes

with temperature, it doesn't change by orders of magnitude,

consequently, I choose the value at 0° C, which, as we all know, is

near to the global mean temperature at sea level. In this I err on

the side of caution, overestimating the heat energy in the calculation

below, because as we all know, both air pressure and temperature drop

with altitude. Also note that while the specific heat value cited

uses the unit °K in the denominator, this is equal to a °C. I use the

tilda (~) as symbol for "circa" or "approximately".

Mass of atmosphere:

5 x 1018 kg

Specific heat of air:

1.005 kJ/kg-°C

Heat needed to raise the temp of the atmosphere 1° C:

~5 x 1018 kJ

Heat needed to raise the temp of the atmosphere 5° C:

~2.5 x 1019 kJ

It is instructive now to compare this quantity of heat with the amount

that would be required to melt sufficient volume of ice from the

Antarctic ice to raise the sea-level by 20-feet as predicted by Al

Gore. Although ice floats, ice and water are very close in density,

so at first approximation, it is fair to say that the volume of sea-

water required to raise sea-level by 20-feet would be equivalent to

the volume of ice that would need to melt to fill the ocean basins in

order to cause that rise. Consequently, let's first roughly calculate

the volume of seawater necessary.

The surface area of the earth can be looked up here. It is 1.5 x 1018

square kilometers, which I convert to 1.5 x 1024 square meters below

for the purpose of our calculation. Al Gore's 20-foot-rise is equal

to ~6 meter. Let's use the commonly cited figure that 70% of the

earth's surface is covered by the oceans and seas. Accordingly,

Area of earth's surface:

1.5 x 1024 m2

Proportion of earth's surface covered by water:

70%

Area of oceans and seas:

~1 x 1024 m2

Sea level rise predicted by Al Gore:

20 feet = 6 m

Volume of water necessary to raise sea-level 20-feet:

~6 x 1024 m3

Volume of ice that needs to melt to raise sea-level 20-feet:

~6 x 1024 m3

This is where the latent heat of melting comes into the equation. As

we all know, when we drop an ice cube into our glass of water, soft-

drink or adult-beverage, it quickly cools the drink. Heat is

transferred to the ice from the liquid in order to melt the ice; this

loss of heat cools and reduces the temperature of the liquid. This

cooling continues until the ice melts completely.

Scientists have long known that a mixture if ice and water (ice-water)

remains at the freezing / melting point (0° C = 32°F). Adding heat

does NOT change the temperature, it just melts more ice; withdrawing

heat does NOT change the temperature it just freezes more water. The

temperature of ice-water will not rise until all the ice is melted;

conversely, the temperature of ice-water will not fall until all the

water is frozen. The heat that would have otherwise raised the ice

temperature is somehow "stored" in the melt water - hence "latent

heat".

As an aside, the transformation of the latent-heat of steam into work

via steam-engines has had, and continues to have, vast industrial

importance. The early systematic study of steam-engines in order to

improve their performance, laid the groundwork for the science of

thermodynamics, which undergirds essentially all of physics and

chemistry.

It turns out that latent heats of melting (and evaporation) are

generally very large quantities when compared to the amount of heat

necessary to change temperatures. Also, as usual in such analyses we

normalize to units of mass. Since the density of water/ice is roughly

a thousand times higher than air, this also greatly impacts the

magnitudes of energy involved, as you will see below. So let's

proceed with the calculation.

The latent heat of melting of water can be looked up here. It is 334

kJ/kg of water. One of the benefits of the metric system is that 1 ml

= 1 cm3 = 1 g of water; this "built in" conversion simplifies many

engineering calculations. Remembering this fact, we do not need to

look up the density of water. Converting this density, 1g/cm3, to MKS

units, yields density of water = 1000 kg/m3. We now have all our data

for the rough calculation:

Volume of ice that needs to melt (from above):

~6 x 1024 m3

Density of water and ice:

1000 kg/m3

Mass of ice that needs to melt:

~6 x 1027 kg

Latent heat of melting for water

3.34 x 102 kJ/kg

Heat necessary to melt ice to achieve 20-foot sea-level rise

~ 2 x 1030 kJ

Following this "back of the envelope" calculation, let's compare the

two energy values:

Heat needed to raise the temp of the atmosphere 5° C:

~2.5 x 1019 kJ

Heat necessary to melt ice to achieve 20-foot sea-level rise

~2 x 1030 kJ

There is a difference of over ten orders of magnitude between these

two figures (1010 = 10 billion). Even if I am wrong by an order of

magnitude or more, there is still an enormous difference. This does

NOT mean that ice caps have not melted in the distant past nor that

ice-age glaciers have not grown to cover much of the northern

hemisphere; it simply means that the time scales involved to move

sufficient quantities of heat to effect such melting or freezing occur

over what we scientists commonly call "geological" time scales, i.e.

hundreds of thousands and millions of years.

Even if sufficient heat is trapped in the atmosphere to raise it the

maximum value predicted by anthropogenic "global warming" alarmists

(5°C) over the next 100 years, hundreds of millions or billions of

times more heat energy must be imparted into the ice-caps to melt

sufficient ice to raise sea-levels the catastrophic levels prophesied

by Al Gore.

I humbly submit that this might constitute a flaw in his equations.

Jerome J. Schmitt has a degree in mechanical engineering from Yale,

and is president of NanoEngineering Corporation.

--------------------------------------------------------------------------------

[*] MKS = meter-kilogram-second instead of cgs units = centimeter-gram-

second for the units of length, mass and time.

[†] -After James Watt, inventor of the first practical steam-engine

which employed a separate condenser.

Al Gore is not a scientist. He is an alarmist who is

claiming outcomes for processes he does not

understand while amassing a huge fortune like a

common charlatan.

.

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