Re: Machinists; critical machining data

On Sat, 23 Jun 2007 09:00:39 -0400, "Proctologically Violated©®"
<entropic3.14decay@xxxxxxxxxxxxxxxxxx> wrote:

All the other balls also have momentum, which, very importantly, happens to
be zero.

Only the scalar of the absolute unitless value.
(0,0,0,0,0,0) is a vector (I included spin it this one <g>). 0 is a scalar.
0 <> (0,0,0,0,0,0) nor can 0 be added or subtracted to/from (0,0,0,0,0,0).
And the vectors are relative to the coordinate system being considered.

BB gets none of this so don't use any "shorthand" or standard
*conventions* as they just confuse him.
--
Cliff
.

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