Re: Replacement transformer for sweeper


"digger odell" <diggerodell@xxxxxxxxx> wrote in message
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On Oct 7, 2:45 pm, "charlie" <charlie.spit...@xxxxxxxxxxxxxxxxxx>
wrote:
"Stormin Mormon" <cayoung61**spambloc...@xxxxxxxxxxx> wrote in message

news:gcefk9$1o4$2@xxxxxxxxxxxxxxxxxxxxxxxxxxxx



My understanding is that too low is no big deal. Too high can "boil" the
moisture out of the batteries.

Where did you learn this wisdom? If I'm wrong, I'd sure like to get the
correct facts.

--
Christopher A. Young
Learn more about Jesus
www.lds.org
.

"charlie" <charlie.spit...@xxxxxxxxxxxxxxxxxx> wrote in message
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you can cause a fire if it's too low. there is no danger if it's too
high.
see if you can google for the manual or specs on it.

you're mistaking what it can provide vs what it is asked to provide by the
load placed upon it.

if a charging circuit attempts to draw too much current from the
transformer, and the transformer has no over temp or over draw circuitry
(i
haven't seen a transformer ever have a fuse), then the transformer will
overheat.

the transformer doesn't provide 600ma all the time; that's just how much
CAN
be drawn out safely. drawing less is not a problem. attempting to draw out
700ma out of a 600ma transformer will cause a fire eventually.

if the load only needs 300ma, then you could provide a transformer that
CAN
provide 10amp (which would be pretty big), but the load will only pull
what
it needs, which would be 300ma, which would be safe.

Ahah! Now for the second part of that question ... Adequate amps but
slightly under the 12 vdc .... say 1.0 Amp and 10 vollts out on the
transformer???

---

it depends upon the load. incorrect voltage could be ok, may be bad for the
load, or the load may simply not work, depending upon how the load is
designed.

if the transformer (which could be either a real transformer (the wallwart
weighs a lot) or an electronic power supply (which would be very small
(think cellphone plug))) outputs 10vdc, and the load requires 12vdc, it
could run inefficiently, burn up, or simply refuse to work. the amount of
power it can provide is really immaterial at this point because you can't
determine what the load design requires.

the bottom line: provide the correct voltage with the correct polarity at a
power equal or higher to what is required by the load.

of course, if the load does something stupid like short out, then if you are
able to deliver a higher amperage than what the correct transformer for the
load is capable of producing, that extra power is going to go somewhere you
don't want it to, usually by either letting out the magic smoke or going
somewhere in a bright flash.


.

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